Solid Ignition TimeThermally thin and thermally thick ignition
What this calculates
This sheet uses basic conduction equations to estimate the time at which a solid will ignite when subjected to a given heat flux. A good example would be if you had a burning pool fire of gasoline, used the “Radiation Pool Fire” spreadsheet to determine the heat flux some distance away where another fuel package was (A wood chair, an upholstered sofa, some cotton drapes, etc.) and used this sheet to determine when that second fuel package would ignite.
We must treat thermally thin items differently than thermally thick items, so there are two different equations provided on this sheet. The thermally thin equation should be used when the item is less than 1/16” thick, anything thicker should use the other equation.
There is one block of cells for thermally thin items, and two blocks of cells on the sheet used for ignition of thermally thick items (the 2nd and 3rd blocks). The two thermally thick blocks are both the same; the only difference is that the first requires user input for the material properties; the other performs the same calculation but uses a dropdown box to select a material and automatically populate the material properties from a table.
How to use it
Determine whether the solid material you are interested in is thermally thin or thick. If it is thin, put the material thickness and thermal properties for density, specific heat, and ignition temperature into the top section. A good place to find these values for some materials would be Quintiere table 3-1 and 4-3 or in Appendix B of the SFPE Handbook. If you can’t find paper, something like wood might be an appropriate substitution. Use the best data you can find and make note of any assumptions that you have made along the way. Determine the heat flux exposure to enter; in the field, this would often come from a radiation calculation (such as the one in the “Radiation Pool Fire” spreadsheet).
For a thermally thick item, check the dropdown box in the bottom section for the material you are interested in. If it (or something close) is there, choose that, then enter the ambient temperature and the heat flux exposure; the ignition time will be reported at the bottom.
If the thermally thick item that you are interested in is not available in the dropdown box, then you will need to look up the appropriate material properties somewhere else and populate the middle block to get your result.
Variables
- t_ig
- Time to ignition [s]
- k
- Thermal conductivity [kW/m·K]
- ρ
- Density of material [kg/m³]
- c
- Specific heat [kJ/kg·K]
- kρc
- Thermal inertia (tabulated, thermally thick) [(kW/m²·K)²·s]
- T_ig
- Ignition temperature [°C]
- T_a
- Initial / ambient temperature [°C]
- ℓ
- Material thickness (thin case) [m]
- q″
- Heat flux exposure [kW/m²]
- q″_cr
- Critical ignition flux (tabulated) [kW/m²]
- C
- Constant — π/4 (no losses) or π/6 (some losses) [—]
Equations
Discussion
A thermally thin object assumes that the item is thin enough that the temperature almost instantly becomes the same on the backside as on the front. As a material gets thicker it becomes less like a thermally thin object. Therefore, we need to account for some length (thickness).
For thermally thick items we are assuming that the backside never heats up to the surface temperature, so mathematically the thickness drops out (we only care about the surface where the ignition is happening here). What comes in though in this case is the thermal conductivity, because now we care how fast heat is conducting away from the surface (where as in the thin case there is nowhere for the heat to go).
The material properties referenced by the drop-down box are from 4-3 of Quintiere’s “Principals of Fire Behavior”.
Worked example
Example 1
What is the ignition time of a 1mm thick piece of yellow pine veneer exposed to a heat flux of 30 kW/m2?
Look up the thermal properties of yellow pine; table B.7 of the SFPE Handbook has the following:
Density = 640 kg/m3
Specific Heat = 2.8 kJ/kgK (which is equivalent to kJ/kgC which the spreadsheet uses)
Thermal conductivity = 0.147 W/mC we need to divide that by 1000 to fit the units in the spreadsheet of kW/mK, so it becomes 0.000147 (we won’t need this for the thermally thin calculation, but would for thermally thick)
Ignition temperature is not in that table, so a quick Google search on ignition temperature of yellow pine results in finding this paper:
Babrauskas, V., Ignition of Wood: A Review of the State of the Art, pp. 71-88 in Interflam 2001, Interscience Communications Ltd., London (2001).
The paper has a wide range of test methods and sample types, but it seems like the most relevant ones are between 350 and 400 C for ignition temperature, so I would run the calculations for both of those to provide a range.
1mm is considered thermally thin, so entering the thermal properties into the top block of cells, assuming an ambient temperature of 20 degrees C since none was specified and putting in the given thickness and heat flux exposure gives:
t = 19.71 seconds for an ignition temperature of 350 degrees C
t = 22.70 seconds for an ignition temperature of 400 degrees C
The small range gives a level of comfort that it isn’t highly dependent on having the perfect ignition temperature. To be on the safe side I might say that the ignition time would be between 20 and 25 seconds.
Example 2
What is the ignition time of a 30mm thick piece of yellow pine exposed to a heat flux of 30 kW/m2?
This is very similar to the example above, but now we have a thermally thick item.
I might start by looking at the dropdown box for a similar material. Although it is sort of like pine, I know that “Douglas Fir Particle Board” has a lot of other stuff in it and isn’t really that much like a piece of wood. The closest thing might be “Plywood, plain (0.635 cm)”.
Selecting that and putting the ambient temperature and the heat flux in will give an ignition time of just under 55 seconds.
That is a good starting point, but since we have already looked up the thermal properties specific to yellow pine, it might be better to enter them into the middle block of cells. This will result in an ignition time of about 33 seconds.
References
- Quintiere, J. G., Principles of Fire Behavior, Chapter 4 — equations 4-2 and 4-3.
- Thermal inertia, ignition temperatures, and critical fluxes from Quintiere, Table 4-3.